1.5x^2-6x-4.2=0

Solution for 1.5x^2-6x-4.2=0 equation:

1.5x^2-6x-4.2=0

a = 1.5; b = -6; c = -4.2;
Δ = b2-4ac
Δ = -62-4·1.5·(-4.2)
Δ = 61.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{61.2}}{2*1.5}=\frac{6-\sqrt{61.2}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{61.2}}{2*1.5}=\frac{6+\sqrt{61.2}}{3}
$